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3x^2+7x-306=0
a = 3; b = 7; c = -306;
Δ = b2-4ac
Δ = 72-4·3·(-306)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-61}{2*3}=\frac{-68}{6} =-11+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+61}{2*3}=\frac{54}{6} =9 $
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